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Basile [38]
3 years ago
9

Find the sum of 6x2 + 10x – 1 and -5x2 – 2x + 1.

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0
-22 and -11 is ur answer I think
Stolb23 [73]3 years ago
4 0

Answer:

x2+8x

Step-by-step explanation:

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Literal Equations: d=gt^2+vt for v
kaheart [24]
d=gt^2+vt\\
vt=d-gt^2\\
v=\dfrac{d-gt^2}{t}
5 0
3 years ago
Uh please help 8x-4y=-4 <br> -3x+4y=5 <br> Subtract second equation from the first
crimeas [40]

Answer:

11x -8y = -9

Step-by-step explanation:

8x-4y=-4

-3x+4y=5

Subtract the second equation from the first

8x-4y=-4

-(-3x+4y=5)

-----------------------------

Distribute the minus sign

  8x-4y=-4

+(3x-4y=-5)

-----------------------------

11x -8y = -9

5 0
3 years ago
What is the value for x
Step2247 [10]

this is an isosceles triangle... meaning that the two base angles will be equal.

180 - 38 =  142

142 / 2 = 71

x = 71

6 0
3 years ago
Verifying Properties of logarithms In Exercise,use a graphing utility to verify that the functions are equivalent for x &gt; 0.
Ede4ka [16]

Answer:

Applying Quotient and power rule. Graphically, for x>0 both curves coincide.

Step-by-step explanation:

1) Firstly, by applying the Quotient and then the Power Rule, we have a subtraction of the argument and, finally the exponent turns to be the coefficient. As it follows:

lnx=log_{e}x\\\\f(x) = ln({\frac{x^{2}}{4}})\Rightarrow f(x)=ln{x^2}-ln4\Rightarrow f(x)=2lnx-ln4\\g(x) = 2 ln x - ln 4

2) Check the graph below to see this equivalence. to see x>0 they  both coincide.

7 0
3 years ago
Find the missing dimension use the scale factor 1:12 model 32 cm find the actual in m
gizmo_the_mogwai [7]

Given:

The scale factor is 1:12.

Dimension of model = 32 cm

To find:

The actual dimension in m.

Solution:

Let x be the actual dimension.

The scale factor is 1:12 and the dimension of model is 32 cm.

\dfrac{1}{12}=\dfrac{32}{x}

On cross multiplication, we get

x=32\times 12

x=384\ cm

x=3.84\ m             [\because 1\ m=100\ cm]

Therefore, the actual dimension is 3.84 m.

6 0
2 years ago
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