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2 years ago

Plz help im stuck

Mathematics

1 answer:

nignag [31]2 years ago

5 0

Here you go I think lol

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Alonzo wrote the equation x=2+4y-5 solve for y

kati45 [8]

if x= 2+4y-5 then x-2 +5 = 4y so y = (x-2+5) /4 = ( x+3) /4

conclusion y = (x+3)/4

3 0

2 years ago

5(x+2)=6x+3x-14 please solve

zavuch27 [327]

Answer:

5(x+2)=6x+3x−14

Step 1: Simplify both sides of the equation.

5(x+2)=6x+3x−14

(5)(x)+(5)(2)=6x+3x+−14(Distribute)

5x+10=6x+3x+−14

5x+10=(6x+3x)+(−14)(Combine Like Terms)

5x+10=9x+−14

5x+10=9x−14

Step 2: Subtract 9x from both sides.

5x+10−9x=9x−14−9x

−4x+10=−14

Step 3: Subtract 10 from both sides.

−4x+10−10=−14−10

−4x=−24

Step 4: Divide both sides by -4.

−4x

−4

−24

−4

x=6

Answer:

x=6

7 0

2 years ago

What is ¼×-8 for math?

navik [9.2K]

1/4 * -8= -8/4=-2
Basically act as if -8 has a denominator of 1 and just multiply across.

- Hope this helps :)

3 0

2 years ago

Read 2 more answers

Mike said last week I ran 15 miles further than Bell. Pete said last week I ran 1 mile less than three times as far as Bill. If

disa [49]

Answer:

The distance cover by Bell is 8 miles .

Step-by-step explanation:

Given as :

The distance cover by Mike = The distance cover by Pete = D miles

Let The distance cover by Bell = d miles

The distance cover by Mike = 15 miles + distance cover by Bell

i.e D = 15 + d ............1

Again

The distance cover by Pete = three time distance cover by Bell - 1 miles

i.e D = 3 × B - 1

Or, D = 3 d - 1 ............2

Now, Solving equation 1 and 2

So, 15 + d = 3 d - 1

Or, 3 d - d = 15 + 1

Or, 2 d = 16

∴ d = $\dfrac{16}{2}$

i.e d = 8 miles

So,The distance cover by Bell = d = 8 miles

Hence, The distance cover by Bell is 8 miles . Answer

6 0

2 years ago

Which expression is equivalent to -6x3.x*y2*y6?<br>0 6x²y3<br>0 6x²y12<br>0 6x²y3<br>0 6x²y12

Lelechka [254]

Answer:

(-6x^3 )(x)( y^2)(y^6) is equal to −6x^4y^8

6 0

2 years ago