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tigry1 [53]
2 years ago
13

If AX contains hex information 2111 and BX contains hex information 4333, what is the content in BX in hex format after performi

ng ASM instruction ADD BX, AX
Computers and Technology
1 answer:
il63 [147K]2 years ago
7 0

Answer:

BX will hold 6444 in hex format.

Explanation:

From the given information:

We need to understand that AX is 64-bit hex number.

When performing ASM instruction (Assembly language instruction),

The addition of 2111 + 4333 = 6444 will be in BX.

This is because ADD, BX, AX will add bx and ax; and the final outcome will be stored in BX.

∴

BX will hold 6444 in hex format.

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Answer:

#include<iostream>

using namespace std;

int main(){

   //initialize

   int a, b,c;

   //print the message

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   //store in the variables

   cin>>a>>b>>c;

   //if-else statement for checking the conditions  

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   }else if(a != b && b != c && a != c ){

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   }

   return 0;

}

Explanation:

Create the main function and declare the three variables for the length of the sides of the triangle.

print the message on the screen for the user. Then the user enters the values and its store in the variables a, b, and c.

use the if-else statement for checking the conditions.

Equilateral triangle: all sides of the triangle are equal.

if condition true, print the equilateral triangle.

Scalene triangle: all sides of the triangle are not equal.

if condition true, print the Scalene triangle.

if both conditions is not true, then, the program moves to else part and print isosceles.

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