Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
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A quick format<span> changes the file system while the </span>full format<span> also checks the </span>drive for bad sectors. <span>The scan for bad sectors is the reason why the Full </span>format<span> takes twice as long as the </span>Quick format<span>. If you choose the </span>Quick format<span> option, the </span>format<span> removes address files from the partition, but does not scan the disk for bad sectors.</span>
Answer:
d.photographers who follow stars to take pictures
Answer:
- All variable names must begin with a letter of the alphabet or an. underscore( _ ).
-After the first initial letter, variable names can also contain letters and numbers.
-Uppercase characters are distinct from lowercase characters.
-You cannot use a C++ keyword as a variable name.
