Answer:
It's 15^7/4
Basically just switch what you have for b and c and it'll be right
It is already given in the question that the combined weight of two rocks is 2 /1/2 pounds. The weight of rock A is also known and it is 1/7 of the total weight of the two rocks. This is enough to find the desired solution.
Now
Total weight of the two rocks = 2 1/2 pounds
= 5/2 pounds
Then
Weight of Rock A = (5/2)/(1/7) pounds
= (5 * 7)/2 pounds
= 35/2 pounds
17 1/2 pounds
So Rock A weighs 17 1/2 pounds. This is the weight of Rock A and it is only required for this question. If you are eager to find the weight of rock B then you have to subtract the weight of Rock A form the total weight of the two rocks.
Answer:
x=y+c/a
Step-by-step explanation:
Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
