Solve y = ax? + c for x.

Please help its past due!

Olenka [21]

A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2).

rule (x + 7, y − 1)

To find new coordinates we add 7 with x and subtract 1 from y

A(−2, 2) -----> A' (5,1)

B(−2, 4) -------> B' (5, 3)

C(2, 4) ---------> C' (9, 3)

D(2, 2) -------->D' (9, 1)

Characteristics

When we connect all the points by line segments, the line A'B' will be parallel to C'D'.

Also, B'C' parallel to A'D'.

All the four lines forms a rectangle .

6 0

4 years ago

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Find the slope of the line passing through the points (8,2) and (8,-5)

Delvig [45]

Step-by-step explanation:

m=y-y¹/x-x¹

=-5-2/8-8

=-7/1

=-7

7 0

3 years ago

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Testing for a disease can be made more efficient by combining samples. If the samples from four people are combined and the mixt

Ilya [14]

Answer:

There is a 34.39% probability of a positive result for four samples combined into one mixture.

This probability is not low enough so that further testing of the individual samples is rarely necessary,

Step-by-step explanation:

There are only two possible outcomes. Either a sample tests positive, or it does not, so we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses x is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

There are four samples, so $n = 4$

Each sample has a probability of 0.1 of being positive, so $\pi = 0.1$ .

Assuming the probability of a single sample testing positive is 0.1, find the probability of a positive result for four samples combined into one mixture.

If any sample is positive, the result of the four samples is positive. So this is $P(X>0)$ . Either the number of positive samples is 0, or it is greater than 0. The sum of the probabilities is decimal 1. So:

$P(X = 0) + P(X>0) = 1$

$P(X>0) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{4,0}.(0.10)^{0}.(0.9)^{4} = 0.6561$

$P(X>0) = 1 - P(X = 0) = 1 - 0.6561 = 0.3439$

There is a 34.39% probability of a positive result for four samples combined into one mixture.

This probability if larger than 5%, so it is not low enough so that further testing of the individual samples is rarely necessary.

4 0

4 years ago

Which best explains why the rotation represents an

Alinara [238K]

The best explanation for why the rotation is isometric is "The rectangle did not change shape or size". Hence the second option is the right choice.

There are four main categories of transformations:

Translation (figure slides in any direction)
Reflection (figure flips over a line)
Rotation (figure turns about a fixed point)
Dilation (the figure is enlarged or reduced)

A stiff transformation known as an isometry maintains perimeter and area while also preserving length and angle measurements. In other words, there is congruence between the preimage and the image. Translations, reflections, and rotations are therefore isometric, but dilations are not since the image and preimage are comparable, rather than congruent figures.

The transformation in the question will be isometric when the preimage of the rectangle before 360° rotation, will be congruent to the image after the rotation.

The congruency is best described by the option "The rectangle did not change shape or size", as that is the basis of congruency.

Thus, the best explanation for why the rotation is isometric is "The rectangle did not change shape or size". Hence the second option is the right choice.

Learn more about isometric transformations at

brainly.com/question/24095450

#SPJ4

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