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torisob [31]
3 years ago
7

A student answers 9 questions

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0
75%


Explanation:

To find the answer you would divide 9/12 and you get .75, then you move the decimal point to the right twice to get your percentage
brilliants [131]3 years ago
4 0

Answer:

75%

Step-by-step explanation:

  1. \frac{9}{12} = 9 ÷ 12
  2. 9 ÷ 12 = 0.75
  3. 0.75 × 100 = 75
  4. So, the percent is 75%

I hope this helps!

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If g(x)= square root of 3-5x, find the domain of g'(x).
BaLLatris [955]

Answer:

domain: x>3/5

Step-by-step explanation:

First we need to derive our function g(x) to get a new function g'(x)

To do this we will have to apply chain rule because we have an inner and outer functions.

Our G(x) = square root(3-5x)

Chain rule formula states that: d/dx(g(f(x)) = g'(f(x))f'(x)

where d/dx(g(f(x)) = g'(x)

g(x) is the outer function which is x^1/2

f(x) is our inner function which is 3-5x

therefore f'(x)= 1/2x^(-1/2) and f'(x) = -5

g'(f(x)) = -1/2(3-5x)^(-1/2)

Applying chain rule then g'(x) = 1/2 (3-5x)^(-/1/2)*(-5)

But the domain is the values of x where the function g'(x) is not defined

In this case it will be 3-5x > 0, because 3-5x is a denominator and anything divide by zero is infinity/undefined

which gives us x >3/5

5 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
7. Look at this figure
kap26 [50]

Answer:

thx for the 32 points

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
According to the rule of 72, in about how many years will $80 be worth $40 if
ludmilkaskok [199]

Answer:

24 Years

Step-by-step explanation:

Rule of 72 is an approximation that you can use to estimate the time it will take for something to double in value at a compound rate of interest

use the following equation

72/(i*100)

we have

72/(.03*100)

72/3=24

3 0
2 years ago
A 12-gallon tub has a faucet that lets water in at a rate of 3 gallons per minute, and a drain that lets water out at a rate of
sergiy2304 [10]
Vol of water required to fill up the tub = 12-3 = 9
Rate of water per min  =    3 -1.5  = 1.5/min
Using the formula           vol   =   rt
                                            t = v/r
                                            t =    9/1.5    =   6
  time taken  =    6 mins



6 0
3 years ago
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