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torisob [31]
3 years ago
7

A student answers 9 questions

Mathematics
2 answers:
Nana76 [90]3 years ago
6 0
75%


Explanation:

To find the answer you would divide 9/12 and you get .75, then you move the decimal point to the right twice to get your percentage
brilliants [131]3 years ago
4 0

Answer:

75%

Step-by-step explanation:

  1. \frac{9}{12} = 9 ÷ 12
  2. 9 ÷ 12 = 0.75
  3. 0.75 × 100 = 75
  4. So, the percent is 75%

I hope this helps!

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A function and its inverse are shown on the graph. Which statement describes the relationship between the function and its inver
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Answer:

Option (B)

Step-by-step explanation:

Domain of function is defined by the set of x-values (input values) and Range of a function is a set of y-values (output values).

From the graph attached,

Domain of f(x) → Set of all real numbers

Range of f(x) → y-values > 0

Domain of f^{-1}(x) → Set of all real numbers

Range of f^{-1}(x) → y < 2

Therefore, domain of both the functions is a set of all real numbers.

Option (B) is the correct option.

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Distribute 2 inside the parentheses.

-88 = 2 + 10m - 10

Combine like terms on the right side.

-88 = -8 + 10m

Add 8 to both sides.

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Divide both sides by 10.

\boxed {m = -8}

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Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

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