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matrenka [14]
3 years ago
15

Is seven eighths greater than two eights

Mathematics
2 answers:
o-na [289]3 years ago
8 0

It is because there are 7 1/8 and it is bigger than 2 1/8.
Tamiku [17]3 years ago
6 0
yes<u /><u /><u> it is greater than two eights

</u>


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the area of rectangular park is 3/5 square mile, the length of the park is 7/8 mile,what is the width of the park
Luba_88 [7]
Area=LengthxWidth so 3/5=7/8xWidth. To get width by itself you must divide both sides by 7/8. When dividing fractions you can flip the fraction and multiply so multiply (3/5)(8/7). To do this just multiply the numerators and denominators to get 24/35 so width = 24/35
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3 years ago
The conditional relative frequency table was generated using data that compares the number of boys and girls who pack their lunc
pochemuha

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734y 87tt795795708 679 ft

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2 years ago
Outline the process for inscribing a regular hexagon in a circle. Perform the construction in GeoGebra
mr_godi [17]

The following are the general steps to draw a hexagon inscribed in a circle:

First draw a circle with center A through B:

Then the intersection points will be vertex C and vertex D of the hexagon. Doing this for each vertex (from left to right) we will get the following:

4 0
1 year ago
The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

5 0
3 years ago
What is the value of the arithmetic series below?
RoseWind [281]

Answer:

- 494

Step-by-step explanation:

Breaking down the summation into it;s component parts

= 4k - \frac{3}{2} k(k + 1) ← substitute k = 19

= (4 × 19 ) - 1.5 × (19 × 20)

= 76 - (1.5 × 380)

= 76 - 570

= 494

3 0
3 years ago
Read 2 more answers
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