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matrenka [14]
3 years ago
15

Is seven eighths greater than two eights

Mathematics
2 answers:
o-na [289]3 years ago
8 0

It is because there are 7 1/8 and it is bigger than 2 1/8.
Tamiku [17]3 years ago
6 0
yes<u /><u /><u> it is greater than two eights

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Just runs 11 miles in 67 minutes how many miles does he run per minute<br>​
alina1380 [7]

Answer

Just runs 7 minutes per mile

Step by Step explanation

Divide 11 by both numbers which leaves you with

1/6

Because you have to divide 11 by 11 and 67 by 11

when you calculate it you get 6.090909091

so you can round it to 7.

8 0
3 years ago
What is the discriminant of the quadratic equation?
Kipish [7]

Answer:

The discriminant is the part under the square root in the quadratic formula, b²-4ac. If it is more than 0, the equation has two real solutions. If it's less than 0, there are no solutions. If it's equal to 0, there is one solution.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A 16 foot ladder rests against the side of a house and the base of the ladder is 4 feet away. How high above the ground is the t
PtichkaEL [24]

Answer:

  15.5 ft

Step-by-step explanation:

The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...

  x^2 + (4 ft)^2 = (16 ft)^2

  x^2 = 240 ft^2 . . . . . . subtract 16 ft^2

  x ≈ 15.5 ft . . . . . . . . . . take the square root

The top of the ladder is about 15.5 ft above the ground.

8 0
3 years ago
Ax-bx+y=z the formula that could be used to find x
Illusion [34]

ax-bx+y=z the formula that could be used to find x

Answer:

<h2>x=z−y/a−b</h2>

5 0
3 years ago
Read 2 more answers
Solve the Law of Cosine: c^2 = a^2+ b^2 - 2abcosC for cos C.
Andrew [12]

Answer:

The Law of Cosine :  cos C = \frac{a^{2}+ b^{2}-c^{2}}{2ab}

Step-by-step explanation:

See the figure to understand the proof :

Let A Triangle ABC with sides a,b,c,

Draw a perpendicular on base AC of height H meet at point D

Divide base length b as AD = x -b   and    CD = x

By Pythagoras Theorem

In Triangle BDC             And     In Triangle BDA

a² = h² + x²     (  1  )                        c² = h² + (x-b)²

                                                      c² = h² + x² + b² - 2xb   ...(. 2)

From above eq 1 and 2

c² = (a² - x²) + x² + b² - 2xb

or, c² = a² + b² - 2xb                    .....(3)

Again in ΔBDC

cos C = \frac{BD}{BC}

Or, cos C = \frac{x}{a}

∴ x= a cos C

Now put ht value of x in eq 3

I.e, c² = a² + b² - 2ab cos C

Hence , cos C = \frac{a^{2}+ b^{2}-c^{2}}{2ab}      Proved   Answer

6 0
3 years ago
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