The function f(x) takes on the value 2 when x = -7 and x = -3, and thus the corresponding points are (-7,2) and (-3,2).
The points where g(x) = 0 are called "roots" or "solutions," and is (3,0).
f(x) > g(x) on the approx. interval (-9, -3/4).
The dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
<h3>What is the Pythagoras theorem?</h3>
The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.
We have:
Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The other end of the leash is tied to the top of an 8-foot pole.
After drawing a right-angle triangle from the above information.
Applying Pythagoras' theorem:
60² = 6² + x²
After solving:
x = 59.69 ≈ 59.7 foot
Thus, the dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.
Learn more about Pythagoras' theorem here:
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Answer:
We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because
✔ all radii of the same circle are congruent.
We also know that AC ≅ BC since
✔ tangents to a circle that intersect are congruent.
Using the reflexive property, we see that
✔ side CO is congruent to side CO.
Therefore, we conclude that △ACO is congruent to △BCO by the
✔ SSS congruence theorem.
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Answer:
6.33
Step-by-step explanation: