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3 years ago

Find the slope of a line that passes through the points (-2,6) and (8,4)

Mathematics

2 answers:

Alexxandr [17]3 years ago

8 0

Answer:

tatagagffgfgsfgsdfhsfhsetywe6

Step-by-step explanation:

Scrat [10]3 years ago

7 0

Answer:

-1/5

Step-by-step explanation:

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Complete the Square:<br> 5x^2+16x-40=8<br> (please show your steps)

Sav [38]

Answer:

Step-by-step explanation:

divide through by the coefficient of $x^{2}$

$\frac{5x^{2} }{5}$ + $\frac{16x}{5} + \frac{-40}{5} = \frac{8}{5}$

$x^{2} +\frac{16}{5}x -8 =\frac{8}{5}$

$x^{2} +\frac{16}{5} x = \frac{8}{5} +8$

$x^{2} + \frac{16}{5} x =\frac{48}{5}$

Add half of the square of the coefficient of x to both sides $(\frac{1}{2} X \frac{16}{5} ) ^{2}$

$x^{2} + \frac{16}{5}x + (\frac{1}{2} X \frac{16}{5} )^{2} =$ $\frac{48}{5} +(\frac{1}{2} X \frac{16}{5} )^{2}$

$x^{2} +\frac{16}{5} x +(\frac{16}{10}) ^{2} =\frac{48}{5} +\frac{64}{25}$

$(x +\frac{16}{10})^{2} =\frac{304}{25}$

$x +\frac{16}{10} =$ ± $\sqrt{\frac{304}{25} }$

$x = -\frac{16}{10}$ ± $\sqrt{\frac{304}{25} }$

$x=-\frac{16}{10} + \sqrt{\frac{304}{25} }$ or $-\frac{16}{10} - \sqrt{\frac{304}{25} }$

$x = 1.89$ or -5.09

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3 years ago

a side of a square is eight raised to the three halves power inches. using the area formula a = s2, determine the area of the sq

bixtya [17]

So given s = 8^(3/2) inches

area a = s^2

a = (8^(3/2))^2 = 8^((3/2)*2) = 8^3 = 512 square inches so the 3rd choice is right sure

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Find the slope of a line that passes through the points (-2,6) and (8,4)​

Find the slope of a line that passes through the points (-2,6) and (8,4)