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sweet-ann [11.9K]
3 years ago
5

Did I get this right if it is I will mark you

Mathematics
1 answer:
Leokris [45]3 years ago
6 0

Answer:

Yes, the area is 49 cm^2

Step-by-step explanation:

You might be interested in
3. Given AB with coordinates A(-4,5) and B(12,13). Find the horizontal distance and the vertical
SCORPION-xisa [38]

The required distance would be 17.88 units coordinates A(-4,5) and B(12,13) and the horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

<h3>What is the distance between two points?</h3>

The distance between two points is defined as the length of the line segment between two places representing their distance.

Given AB with coordinates A(-4,5) and B(12,13).

The formula of the distance between two points is A(x₁, y₁) and B(x₂, y₂) is given by: d (A, B) = √ (x₂ – x₁)² + (y₂ – y₁) ².

x₁ = -4, y₁ = 5

x₂ = 12, y₂ = 13

distance = √ (12 – (-4))² + (13 – 5)²

distance = √ (12 + 4)² + (8)²

distance = √ (16)² + (8)²

distance = √ (256 + 64)

distance = √320

distance = 17.88 units

The horizontal distance is 16 units and the vertical distance is 8 units from A to B which are determined by the graphing method.

Learn more about the distance between two points here:

brainly.com/question/15958176

#SPJ1

6 0
1 year ago
What is 23/100 simplified to
IgorC [24]
The simplified answer is 0.23
4 0
3 years ago
Read 2 more answers
Write g-12 in words
larisa [96]
I'm guessing you are looking for an algebraic sentence. In that case, 12 less than g would make sense, or 12 subtracted from g
8 0
3 years ago
Can someone help me and you need to round to nearest whole number
andrew11 [14]

Answer:

look at the picture i have sent

5 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
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