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3 years ago

In the system of equations, which variable would it be easiest to solve for?

Mathematics

2 answers:

alisha [4.7K]3 years ago

5 0

D Itś D DDDDDD DDDDDDDDDDDDDDDDDD

Digiron [165]3 years ago

4 0

Answer:

The easiest way of solving this is to eliminate one of the variables. If you multiply each of the equations by a number so you can add the equations together and have only one variable left, you can solve the single variable equation. Try multiplying the first equation by 11, the second by -10 and adding them, thus eliminating the y variable. After this, substitute that value you have for x and solve for y. I hope this helps.

Step-by-step explanation:

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Sveta_85 [38]

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<u>Multiply</u>

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<u>Multiply</u>

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gavmur [86]

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3 years ago

NO LINKS!! Please help with questions 3 and 4

Taya2010 [7]

Answer:

$\textsf{3.} \quad (x,y) \rightarrow (x-5,y+2)$

$\textsf{4.} \quad (x,y) \rightarrow (x+3,y+1)$

Step-by-step explanation:

<h3><u>Question 3</u></h3>

Given vertices of ΔLMN:

L = (1, -1)
M = (4, 1)
N = (5, -1)

Given vertices of ΔL'M'N':

L' = (-4, 1)
M' = (-1, 3)
N' = (0, 1)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

$x_{M'}-x_M =-1-4=-5 \implies \textsf{5 units left}$

$y_{M'}-y_M =3-1=2 \implies \textsf{2 units up}$

Therefore, the mapping rule for the translation is:

$(x,y) \rightarrow (x-5,y+2)$

<h3><u>Question 4</u></h3>

Given vertices of ΔLMN:

L = (-6, -4)
M = (-5, -1)
N = (-2 -4)

Given vertices of ΔL'M'N':

L' = (-3, -3)
M' = (-2, 0)
N' = (1, -3)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

$x_{L'}-x_L =-3-(-6)=3 \implies \textsf{3 units right}$