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2 years ago

Help me :( .........

Mathematics

2 answers:

arlik [135]2 years ago

6 0

Answer:

B. 16 feet

Step-by-step explanation:

The tree and well are to scale.

6x4 is 24

so that means that 4x4 is 16.

Nat2105 [25]2 years ago

3 0

Answer:

Step-by-step explanation:

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How many tens are in the number 1,384

Andre45 [30]

There are 8 tens in the number 1,384.

Each digit in the number has an equivalent value based on its placement in the number.

1,384 where:

1 is in the thousands value
3 is in the hundreds value
8 is in the tens value
4 is in the ones value

The extended form of 1,384 is:

1 x 1000 + 3 x 100 + 8 x 10 + 4 x 1 = 1,384

1,000 + 300 + 80 + 4 = 1,384

8 x 10 = 80 ; shows that there are 8 10s in the number with a product of 80.

7 0

3 years ago

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1. What is the perimeter, and area, of a square with a side length of 3 inches?

pogonyaev

perimeter: 12 inches

area: 9 inches

8 0

3 years ago

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Help asap (like right now )

Gemiola [76]

Answer:

B) Yes, because the slope is $-\frac{25}{3}$ and the zero is (12, 0)

Step-by-step explanation:

From inspection of the graph:

y-intercept = (0, 100)
Two points: (3, 75) and (6, 50)

$\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{50-75}{6-3}=-\dfrac{25}{3}$

Therefore, the equation of the line in slope-intercept form y = mx + b

(where m is the slope and b is the y-intercept) is:

$y=-\dfrac{25}{3}x+100$

To find the zero (when y = 0), set the equation to zero and solve for x:

$\implies -\dfrac{25}{3}x+100=0$

$\implies \dfrac{25}{3}x=100$

$\implies 25x=300$

$\implies x=12$

Therefore, the zero is at (12, 0)

Therefore, the graph does represent the function because the slope is $-\frac{25}{3}$ and the zero is at (12, 0)

4 0

2 years ago

What is the graph of the function f(x)=x2-9x+20/x-4

Kipish [7]

Y=((x-5)(x-4))/(x-4)

y=x-5

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3 years ago

Find the power series expansion for f(x)= 4/(x+2); x doesn't equal 2, centered at 0

suter [353]

$\dfrac4{x+2}=\dfrac2{1-\left(-\frac x2\right)}=2\displaystyle\sum_{n\ge0}\left(-\frac x2\right)^n$

which is valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

4 0

3 years ago