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Gelneren [198K]
3 years ago
11

A scuba diver ascends 5 3/4 feet to the top of a boat platform. The diver then descends 20 1/8 feet by jumping off the boat. Wri

te and evaluate on subtraction expression to show what lever under sea level the scuba currently is
Mathematics
1 answer:
Nana76 [90]3 years ago
8 0
-15 5/8 feet
5 6/8- 20 1/8
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I don't understand how to do it
leonid [27]
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5 0
3 years ago
Given. Two pair of values x1=5,y1=4,x2=1,y2=1/2. Calculate the Pythagorean triples associated with each pair?
choli [55]
The so-called pythagorean triple will just be the distance between both points,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 5}} &,&{{ 4}}~) 
%  (c,d)
&&(~{{ 1}} &,&{{ \frac{1}{2}}}~)
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf d=\sqrt{(1-5)^2+\left( \frac{1}{2}-4 \right)^2}\implies d=\sqrt{(-4)^2+\left( -\frac{7}{2} \right)^2}
\\\\\\
d=\sqrt{16+\frac{7^2}{2^2}}\implies d=\sqrt{16+\frac{49}{4}}\implies d=\sqrt{\frac{64+49}{4}}
\\\\\\
d=\sqrt{\frac{113}{4}}\implies d=\cfrac{\sqrt{113}}{\sqrt{4}}\implies d=\cfrac{\sqrt{113}}{2}
5 0
3 years ago
Prove that if d|m and d|n, then d|(m+n)
Mila [183]
d\mid m means to say there is some k_1 such that m=dk_1. Similarly, d\mid n is equivalent to saying there exists k_2[/te]x such that [tex]n=dk_2.

Now, m+n=dk_1+dk_2=d(k_1+k_2)=dk_3, i.e. there is some k_3 such that m+n is a multiple of d, i.e. d\mid(m+n).
5 0
4 years ago
A man that is 6ft sits next to a tree. His shadow is 27ft. The tree leaves a 81ft shadow. How tall was the tree.
KonstantinChe [14]
Simply cross multiply the proportion of
6/27= x/81 do 6•81 divided my 27 for your answer which is 18
3 0
4 years ago
Translate into a verbal expression:<br> 3x - 2
Rus_ich [418]

Answer:

three times a number minus two

Step-by-step explanation:

x= times a number

6 0
3 years ago
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