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nordsb [41]
3 years ago
10

The midpoint of is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

(-2,3)

Step-by-step explanation:

(-6+2)/2 , (-2+-6)/2

(-2,3)

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Answer:

<u>36 in²</u>

Step-by-step explanation:

<u>Area of the figure</u>

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12% of what number is 42?
Andreyy89

Answer:

350

Step-by-step explanation:

12% = 0.12

42 / 0.12 = 350

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3 years ago
Which graph represents exponential decay? On a coordinate plane, a straight line has a negative slope. On a coordinate plane, a
RoseWind [281]

Answer:

The correct option is (C).

Step-by-step explanation:

The exponential function representing decay is as follows:

y=y_{0}\cdot e^{kt};\ k

Here,

<em>y</em> = final value  

<em>y</em>₀ = initial value  

<em>k</em> = growth rate  

<em>t</em> = time passed

The graph represents exponential decay is:

"On a coordinate plane, a graph approaches y = 0 in quadrant 1 and curves up into quadrant 2."

Thus, the correct option is (C).

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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