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OLEGan [10]
3 years ago
7

Graph the linear equation y=x-3

Mathematics
1 answer:
IrinaK [193]3 years ago
7 0
Start with a dot on -3 of the y-axis, then use slope 1/1 to go up one and right one, do that until you reach 3 on the x-axis and make a dot, and then just draw a line through both dots.
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seropon [69]

It doesn't, it ends after 32 digits after 0.

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2.2f+0.3f−13−4=<br> Pls hurry!
Aleks [24]

Answer:

-14.5

Step-by-step explanation:

To get the calculator and type 2.2+0.3-13-4

6 0
2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

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2 years ago
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Nutka1998 [239]
1.02 is the answer to your question
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3 years ago
Can anyone help me do or solve these
Ivahew [28]

Answer:I will just post them

Step-by-step explanation:

4 0
2 years ago
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