Apply slip and slide
a^2-3a-4
(a-4)(a+1)
(a-2)(2a+1)
Find zeros
a-2=0
a=2
2a+1=0
2a=-1
a=-1/2
Final answer: {-1/2, 2}
You are almost done!
well, the euation of a circle centered at (h,k) and radius r is
(x-h)²+(y-k)²=r²
so you havve
(x-3)²+(y+5)²=9 (which is correct)
this can be rewritten as
(x-3)²+(y-(-5))²=3²
the center is (3,-5) and the radius is 3
Answer:
It would be -81²x+81x-18= -9x+6
Step-by-step explanation:
When you work equation one you get 18. Then when you work equation two, you get -2/3=-0.666666667
Answer:
Step-by-step explanation:
parallel lines
5p - 3q = -39
- (-2p - 3q = 3)
==> 7p = -42 ==> p = -6
==> p = -6
-2(-6) - 3q = 3 ==> 12 - 3q = 3
==>p = -6
-3q = 3 - 12 ==> -3q = -9
==> p = -6
q = 3
