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Marta_Voda [28]
3 years ago
10

Solve the equation. 6 - x - x = 18

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
6 0
6-x-x=18
-x-x=18-6
-x-x=12
-2x=12
x=12/-2
x=-6
Check: 6- (-6)- (-6) remember - - = +
So basically it's 6+6+6=18
vova2212 [387]3 years ago
4 0
X = -6
6 - -6 - -6 = 18
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Answer: Undefined

Step-by-step explanation:

(slope = m)

m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{4-4}=\frac{3}{0}

(3 divided by 0 is undefined, so the slope is undefined)

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3 years ago
Which equation is the equivalent form of 20(3)^5x = 820?
makvit [3.9K]

Answer:

x=ln(41)/ln(243)

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6 0
2 years ago
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The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.d1d2, where d1 and d2 are the l
AlexFokin [52]

The two equivalent equations are d₁= 2a/d₂ and d₂= 2a/d₁ , Option 2 and 5 is the right answer.

<h3>What is a Rhombus ?</h3>

Rhombus is a quadrilateral with all the sides equal to each other.

It is given that d₁ and d₂ are the lengths of the diagonals.

and Area = a

a = (1/2) d₁ * d₂

  • 2a = d₁ * d₂

       d₁ * d₂ = 2a

       It can be written as

        d₁= 2a/d₂

a = (1/2) d₁ * d₂

  • d₁ * d₂ = 2a

        d₂= 2a/d₁

Therefore Option 2 and 5 are the correct answer.

The options of this question are:

1.  d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2A/d₁

To know more about Rhombus

brainly.com/question/27870968

#SPJ1

3 0
2 years ago
Find the derivative of ln(cosx²).​
RoseWind [281]

Answer:

\displaystyle \frac{dy}{dx} = -2x \tan (x^2)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
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Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = \ln (\cos x^2)

<u>Step 2: Differentiate</u>

  1. Logarithmic Differentiation [Derivative Rule - Chain Rule]:                       \displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}
  2. Trigonometric Differentiation [Derivative Rule - Chain Rule]:                   \displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}
  3. Basic Power Rule:                                                                                         \displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}
  4. Rewrite [Trigonometric Identities]:                                                              \displaystyle y' = -2x \tan (x^2)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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