All categories

2 years ago

Here is a list of numbers: 19, 4, -13, -17, -2, -14, 20, 8, 6 State the median.

Mathematics

1 answer:

denis-greek [22]2 years ago

8 0

Answer:

4 is the median to your problem

You might be interested in

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

3 years ago

4 over 5x minus 8 equals 3. what is x

ehidna [41]

4/5x-8=3
move -8 to the other side and add
4/5x=3+8
4/5x=11
move 5x to the other side and multiply
4=5x*11
4=55x
4/55=x

8 0

1 year ago

I need help with number 7 too.

eimsori [14]

Answer:

Look Below

Step-by-step explanation:

m<1 could be 30

m<2 could be 60

m<3 could be 30

3 0

3 years ago

Read 2 more answers

How many solutions does this equation have?<br><br> –10q = –10q − 7

Salsk061 [2.6K]

Answer:

None (no solutions)

Step-by-step explanation:

-10q=-10q-7 (add 10q to both sides to get the costant 7 by itself)

-10q+10q=-10q+10q-7

0=-7 ( zero will never equal -7 hence there are no solutions to this equation)

8 0

2 years ago

Write 3 more than twice a number is 7 , as a word a statement.

cupoosta [38]

Three plus a number times two.

6 0

2 years ago