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4 years ago

11

What's the value of the X ?

1 answer:

taurus [48]4 years ago

3 0

Question

What's the value of the X ?

Answer:

<h2>39°</h2>

Step-by-step explanation:

The sum of the interior angles is 180° (triangle)

take off from 180° the sum of the know numbers

180 - 102 - 39 = 39° (it is an isosceles triangle, 2 equal angles.)

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Translate "k increased by 5 gives 8" into an algebraic equation.

Arturiano [62]

Answer:

k+5 = 8

Step-by-step explanation:

"k increased by 5 gives 8

increased means add while gives means equals

k+5 = 8

6 0

4 years ago

Factor 3y^2 - 4y. plzzzzzz

Lisa [10]

Answer:

y(3y - 4)

Step-by-step explanation:

$3y^{2} -4y$

Both have y.

Factor y out of $3y^{2} -4y$

$y(3y-4)$

7 0

4 years ago

Find the indefinite integrals

Alexxx [7]

Answer:

Below in bold

Step-by-step explanation:

∫ dx / (x^2√(9-x^2))

Substitute x = 3sinu and dx = 3cosu du

then the √(9-x^2) = √( 9 - 9sin^2u) = 3 cos u and u = arcsin(x/3)

= 3 ∫(csc^2 u du )/ 27

= 1/9 ∫(csc^2 u du

= -1/9 cot u

= -√9-x^2) / 9x.

4 0

3 years ago

I’m really confused on this problem., pls help me!

777dan777 [17]

Answer:

Domain: All Real Numbers

Range: All Real Numbers

Step-by-step explanation:

So the domain of a function can be defined as an interval of x-values, which you can input into the function and get real numbers as an output. Since we have a cube root here, or more specifically an odd nth root, the domain is all real numbers, since cbrt(negative number) will just be a negative number since (negative number * negative number * negative number) = negative number, so there does exist a solution, unlike even nth roots like square root, which is restricted to only positive values inside the radical, otherwise you get non-real solutions.

Now let's look at the range of the function, which can be defined as an interval of y-values which can possibly be outputted by the function.

Since as mentioned before, the cube root isn't limited to a certain interval, and rather all real numbers, the range is also similar, since whenever you have a negative number in the radical, the output will be a negative number, so the range is all real numbers

8 0

2 years ago

Read 2 more answers

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago