Answer:
43.17 ft/s
Step-by-step explanation:
Let the height of the wall is y.
distance of wall from light is 20 feet.
y = 20 tanθ .... (1)
time period, T = 3 second
Differentiate equation (1) with respect to t.
dy/dt = 20 x 2.16
dy/dt = 43.17 ft/s
I believe the answer would be 70 but make sure just in case.
Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
Answer:
20
Step-by-step explanation:
<span>Select one equation and solve it for one of its variables.
In the other equation, substitute for the variable just solved.
Solve the new equation.
<span>Substitute the value found into any equation involving both variables and solve for the other variable. </span></span>
