Answer:
vertical angles, x=5 The angles each measure 35 degrees
Step-by-step explanation:
These are vertical angles, so they are equal
3x+20 = 10x-15
Subtract 3x from each side
3x+20-3x = 10x-13-3x
20 = 7x-15
Add 15 to each side
20+15 = 3x-15+15
35=7x
Divide by 7
35/7 = 7x/7
5 =x
The angles are equal so they each measure
3x+20 = 3(5)+20 = 15+20 = 35
The each measure 35
Answer:
the first one
Step-by-step explanation:
Answer:
it is B.
Step-by-step explanation:
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
its 1
Step-by-step explanation:
it literly says it on the grid and its really simple
