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dlinn [17]
3 years ago
14

16 = s/2 *

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
5 0

Answer:

60

Step-by-step explanation:

emmainna [20.7K]3 years ago
4 0

Step-by-step explanation:

x+8=10

x−4=22

x÷3=6

7x=28

60=30+30=6+6+6+6+6+6+6+6+6+6

a=a

a=b,thenb=a

60=30+30,then30+30=60

ifa=bandb=c,thena=c

60=30+30

30+30=6+6+6+6+6+6+6+6+6+6

60=6+6+6+6+6+6+6+6+6+6

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A ceral company puts a colored ring in each box of cereal. there are 6 different colors.
lozanna [386]

Answer:

2/5

Step-by-step explanation:

Given in the question,

Total number of cereal box = 50

number of cereal box which have blue rings = 15

number of cereal box which have yellow rings = 5

Probability = favorable outcome / total number of outcome

Probability  = (15+5) / 50

Probability  = 20 / 50

Probability  = 2/5

3 0
3 years ago
What it the explicit formula for 8
Alex

Answer:

-8

Step-by-step explanation:

THANKS

3 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br><br> (10,6) and (3,1)
Oksana_A [137]

Answer:

(6.5 , 3.5)

Step-by-step explanation:

Midpoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\\

               =(\frac{10+3}{2},\frac{6+1}{2})\\\\=(\frac{13}{2},\frac{7}{2})\\\\=(6.5,3.5)

8 0
3 years ago
a. Everyone in your class has a cell phone. b. Somebody in your class has seen a foreign movie. c. There is a person in your cla
Montano1993 [528]

Answer:

See below

Step-by-step explanation:

Your question is incomplete, but probably you want to express each statement with propositional calculus.

Let S be the set of all students of your class. Given a variable x, symbolize the statements:

c(x):="x has a cellphone"

f(x):="x has seen a foreign movie"

s(x):="x can swim"

p(x):="x can write proofs"

r(x):="x wants to be rich"

Remember the quantifiers "There exists (∃)" and "For all (∀)". Using the domain of discourse S and the variable x∈S, we can write the statements as:

a) (∀x)(c(x))

b) (∃x)(f(x))

c) (∃x)(¬s(x))

d) (∀x)(p(x))

e) (∃x)(r(x))

6 0
4 years ago
Solve inequality.<br> |3n-2|-2&lt;1
pychu [463]

\text{Hello there! :)}

\boxed{-1/3 < n < 5/3}

|3n - 2| - 2 < 1

\text{Begin simplifying by adding 2 to both sides:}

|3n - 2| < 3

\text{ Solve for the positive and negative solutions:}

3n - 2 < 3\\\\3n < 5\\\\n < 5/3

-(3n - 2) < 3\\\\\text{Switch sign when dividing by a negative:}\\\\3n - 2 > - 3\\\\3n > - 1\\\\n > -1/3

\text{Therefore, the solutions for the inequality are:}\\\\-1/3 < n < 5/3

8 0
4 years ago
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