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zalisa [80]
3 years ago
12

100 POINTS HELP! I WILL GIVE BRAINLIEST TO THE BEST ANSWER FAKE ANSWERS WILL BE REPORTED

Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

1.

In triangle ∆AFD ,∆BGD ,∆CHD

<AFD=<BGD=<CHD

[being corresponding angle]

<DAF=<DBG=<DCH

[being corresponding angle]

<D is common for all.

So

∆AFD ~∆BGD ~∆CHD

[By A .A .A. axiom]

look

again

at picture pasted

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What are the coordinates of point Q?
Lady bird [3.3K]

Answer:

Q (-4, -2); 2 units; Q' will be above the x-axis; 2 unites; no; yes, the y coordinates are multiplied by -1; Q' (-4, 2); R' (-2, 2), S' (1, 5), T' (-2, 5);

Step-by-step explanation:

even after a reflection over the x-axis, each points distance from the x-axis will stay the same

the x-coordinates don't change because the distance from the y-axis stays the same

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2 years ago
Given m||n, find the value of x
fenix001 [56]
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4 0
3 years ago
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tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

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Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

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Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
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Levart [38]

Answer:

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-3x-5=1

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