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2 years ago

Please help immediately

Mathematics

1 answer:

timama [110]2 years ago

8 0

Answer:

Look Below

Step-by-step explanation:

I'm not going to do any of these, i'll just set up the equation for you to find x.

9. 75+x=90

10. x+22=180

11. x=84

12. 82+78+x=180

13. (4x+3)+(x-8)=90

14. (8x+9)+(5x+15)=180 (This was hard to read, check to see if I typed it right.)

15. 2x+4+140=180

16. 4x-13=67+2x

17. 9x+7=115

18. 12x=60

19. 4x=x+21

20. 5x+12+73=180

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Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$

Hence, the correct option is $4\sqrt{3}$ .

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3 years ago

Let G denote the centroid of triangle ABC. If triangle ABG is equilateral with side length 2, then determine the perimeter of tr

zhannawk [14.2K]

We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA= $\sqrt{3}$ . Hence CM=GC+GM=3* $\sqrt{3} /$ . Now, since GM is normal to AB, we have by the pythagoeran theorem that:
$AC^2=AM^2+GM^2=BM^2+GM^2=BC^2$
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3 years ago

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Answer:

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Step-by-step explanation:

Given the function;

y = 2x + 1

when x = 0

y = 2(0)+1

y = 1

Hence the required pair is (0, 1)

when x = -1

y = 2(-1) + 1

y = -2 + 1

y = -1

Hence the coordinate is (-1, -1)

when x = 1

y = 2(1) + 1

y = 2 + 1

y =3

Hence the coordinate is (1, 3)

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2 years ago

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Step-by-step explanation:

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3 years ago

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