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3 years ago

5

Plz help with these ill post more with more points

1 answer:

zaharov [31]3 years ago

5 0

Answer:

I think it is D I'm not sure

Step-by-step explanation:

If two angle and one ️ are congruent to two angles of a second ️ and also if the included sides are congruent, then the ️ are congruent. If in ️ PRQ and TUV, angle P=angle T, angle R=angle and PR=TU, then triangles PRQ is congruent to triangle TUV

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Robin invests $3,210 in an account that is compounded annually and pays

igor_vitrenko [27]

Answer:

the factor is an increasing value of 17/332 or the power of pointed answers of interest of 3.4% which makes it aroujd 2 but doesnt matter because its the factor and not issued investment

Step-by-step explanation:

8 0

3 years ago

Which of the following is a logarithmic function?

Komok [63]

Answer:

A) y = $log_{3}(x)$ is logarithmic function.

Step-by-step explanation:

Given : Options.

To find : which of the following is a logarithmic function.

Solution : We have given option

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We can see from given options

y = $log_{3}(x)$ is logarithmic function.

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4 0

3 years ago

Read 2 more answers

A game and a controller are on sale for 45% off. The regular price of the game is $80. The regular price of the controller is $1

erma4kov [3.2K]

It is 36

Explanation:
80/100 = 0.8
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3 0

3 years ago

let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a

Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

<em>p</em> ⇒ <em>q</em>

is

¬<em>q</em> ⇒ ¬<em>p</em>

In this case, the contrapositive claims that

"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."

The first equation is captured by a system of linear equations,

$\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}$

or in matrix form,

$\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}$

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

$\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0$

and this is what we wanted to prove. QED

3 0

3 years ago

Find the lowest common denominator for the set of fractions.

PtichkaEL [24]

I’m saying (x+2) if you factor the denominators

3 0

3 years ago