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Kobotan [32]
3 years ago
14

Robin invests $3,210 in an account that is compounded annually and pays

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

the factor is an increasing value of 17/332 or the power of pointed answers of interest of 3.4% which makes it aroujd 2 but doesnt matter because its the factor and not issued investment

Step-by-step explanation:

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Please Answer
Lapatulllka [165]

Answer:

Part A: C. 4 to 1

Part B: 2

Step-by-step explanation:

<h3>Part A: </h3>

What is the ratio of the number of students receiving a C and the number of students receiving an A?

<u>As per table given:</u>

  • 12 students received a C and 3 students received a A

The ratio C/A is:

  • 12/3 = 4/1

The correct answer choice is:

  • C. 4 to 1
<h3>Part B: </h3>

Complete the statement:

For every student receiving a D, ______ students received a B.

<u>As per table given:</u>

  • 4 students received a D and 8 students received a B

<u>The ratio D/B is:</u>

  • 4/8 = 1/2

<u>The statement is:</u>

  • For every student receiving a D, 2 students received a B.
7 0
3 years ago
In the fraction 5_8what is the term used to designate the 5
jek_recluse [69]
\frac{Numerator}{Denominator}


In this case the 5 is on top so it is the Numerator
3 0
3 years ago
A particle moves on a circle through points which been marked 0,1,2,3,4 (in a clockwise order). At each step it has a probabilit
Sedaia [141]

Answer:

Step-by-step explanation:

Given data:

SS={0,1,2,3,4}

Let probability of moving to the right be = P

Then probability of moving to the left is =1-P

The transition probability matrix is:

\left[\begin{array}{ccccc}1&P&0&0&0\\1-P&1&P&0&0\\0&1-P&1&P&0\\0&0&1-P&1&P\\0&0&0&1-P&1\end{array}\right]

Calculating the limiting probabilities:

π0=π0+Pπ1                 eq(1)

π1=(1-P)π0+π1+Pπ2     eq(2)

π2=(1-P)π1+π2+Pπ3    eq(3)

π3=(1-P)π2+π3+Pπ4    eq(4)

π4=(1-P)π3+π4             eq(5)

π0+π1+π2+π3+π4=1

π0-π0-Pπ1=0

→π1 = 0

substituting value of π1  in eq(2)

(1-P)π0+Pπ2=0

from

π2=(1-P)π1+π2+Pπ3  

we get

(1-P)π1+Pπ3 = 0

from

π3=(1-P)π2+π3+Pπ4

we get

(1-P)π2+Pπ4 =0

from π4=(1-P)π3+π4  

→π3=0

substituting values of π1 and π3 in eq(3)

→π2=0

Now

π0+π1+π2+π3+π4=0

π0+π4=1

π0=0.5

π4=0.5

So limiting probabilities are {0.5,0,0,0,0.5}

4 0
3 years ago
How to solve lim and sin?
Galina-37 [17]

Answer:

No entendí :)

Step-by-step explanation:

6 0
3 years ago
2 What is the equation of the axis of symmetry of the
mixas84 [53]

Answer:2

Step-by-step explanation:

5 0
3 years ago
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