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omeli [17]
3 years ago
7

Need Answer Immediately!!!!!

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0
<h2>Answer:</h2>

y = \frac{-5}{4}x + 3

<h2>Step-by-step explanation:</h2>

As shown in the graph, the line is a straight line. Therefore, the general equation of a straight line can be employed to derive the equation of the line.

The general equation of a straight line is given by:

y = mx + c <em>or            </em>-------------(i)

y - y₁ = m(x - x₁)        -----------------(ii)

Where;

y₁ is the value of a point on the y-axis

x₁ is the value of the same point on the x-axis

m is the slope of the line

c is the y-intercept of the line.

Equation (i) is the slope-intercept form of a line

Steps:

(i) Pick any two points (x₁, y₁) and (x₂, y₂) on the line.

In this case, let;

(x₁, y₁) = (0, 3)

(x₂, y₂) = (4, -2)

(ii) With the chosen points, calculate the slope <em>m</em> given by;

m = \frac{y_2 - y_1}{x_2-x_1}

m = \frac{-2-3}{4-0}

m = \frac{-5}{4}

(iii) Substitute the first point (x₁, y₁) = (0, 3) and m = \frac{-5}{4} into equation (ii) as follows;

y - 3 = \frac{-5}{4}(x - 0)

(iv) Solve for y from (iii)

y - 3 = \frac{-5}{4}x

y = \frac{-5}{4}x + 3 [This is the slope intercept form of the line]

Where the slope is \frac{-5}{4} and the intercept is 3

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3 years ago
Determine the number of possible triangles, ABC, that can be formed given angle A = 30°, a = 4, and b = 6.
Sophie [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

using Sine Law,

\frac{sinA}{a}=\frac{sinB}{b}

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angle B = 48.6

Another angle will be

angle B' = 180-48.6 = 131.4

considering angle B, angle C = 180 - (48.6+30)=101.4

considering angle B', angle C' = 180-(131.4+30)=18.6

\frac{sinA}{a}=\frac{sinC}{c}

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Similarly, finding c'

\frac{sinA}{a}=\frac{sinC'}{c'}

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c'=2.55

Hence two triangles are possible with below details:  :   Answer

A = 30, B = 48.6, C = 101.4, c = 7.84

A = 30, B' = 131.4, C' = 18.6, c' = 2.55

Hope it will help :)

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