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3 years ago

Calcular s, si la figura es un prisma a=15m2, b=20m2

Mathematics

1 answer:

julia-pushkina [17]3 years ago

6 0

Celculate the figures by using the numbers,with letters

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Need some help (I get like no change back at all I just want to know the process of doing this)Im usually good at math but congr

Nikolay [14]

(you and 3 friends so we have 4 person
<span>The group plans to ride each water ride twice.</span>
so for each person we will pay 2(4.5+4+3.5)=2*12=24$
and for 4 person 24*4=96$
100-96=4$
Answer: 4$)

but looking on gaven answers i understood that each person pay only for himself!
so you paid 24$ and will get back 100-24=76$
Answer: 76$

8 0

4 years ago

using the pythagorean theorem find the area of an equilateral triangle whose side measures 7 units find the area to the nearest

Molodets [167]

<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
</span>

7 0

3 years ago

Read 2 more answers

After 4 days, a bookstore has 140 copies of a new title still on hand. After 9 days, the bookstore has 50 copies still on hand.

alexira [117]

Answer:

$c(t) =-18t +212$

Step-by-step explanation:

Given

$(t_1,c_1) = (4,140)$

$(t_2,c_2) = (9,50)$

Required

Determine the equation

First, we calculate the slope (m)

$m = \frac{c_2 - c_1}{t_2 - t_1}$

$m = \frac{50 - 140}{9-4}$

$m = \frac{-90}{5}$

$m = -18$

The equation is then calculated as:

$c =m(t - t_1) + c_1$

$c =-18*(t - 4) + 140$

$c =-18t +72 + 140$

$c =-18t +212$

Hence, the function is:

$c(t) =-18t +212$

8 0

3 years ago

HELP PLEASE!!!!!!!!!!!

tamaranim1 [39]

Answer:

First one hypotenuse leg

Step-by-step explanation:

4 0

3 years ago

7+3√5/3+√5 - 7-3√5/3-√5 = a + b√5

daser333 [38]

<h3>Given:-</h3>

$\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } = a + \sqrt{5} b \\$

The value of a and b

<h3>Solution:-</h3>

$\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } = a + \sqrt{5} b \\$

$\\ \sf \implies\frac{( \: 7 + 3 \sqrt{5} \: \: ( 3 - \sqrt{5}) \: \: - 7 - 3 \sqrt{5} \: \: ( 3 + \sqrt{5}) \: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{( \: 21 - 7 \sqrt{5} \: + 9 \sqrt{5} - 15) \: \: - ( \: 21 + 7 \sqrt{5} \: - 9 \sqrt{5} + 15)\: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{( \: 6 + 2 \sqrt{5} ) \: \: - ( \: 6 - 2 \sqrt{5} )\: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 6 + 2 \sqrt{5} \: \: - \: \: 6 - 2 \sqrt{5} \: }{(3 + \sqrt{5}) \: \:(3 + \sqrt{5}) } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{3 {}^{2} - {\sqrt{5} }^{2} } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{ \: \: \: \: 9 - 5 \: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: 4 \sqrt{5} \: \: }{ \: \: \: \: 4 \: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies\frac{\: \cancel{4 } \sqrt{5} \: \: }{ \: \: \: \: \cancel{4 }\: \: \: } = a + \sqrt{5} \: b\\$

$\\ \sf \implies \: \sqrt{5} = a + \sqrt{5} \: b\\$

we can also write it as ;

$\\ \sf \implies \: 0 + \sqrt{5} = a + \sqrt{5} \: b\\$

★<u> </u><u>Henceforth, the value of a and b are</u> :

→ a = 0

→ b = 1

6 0

2 years ago

Read 2 more answers