Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:

Using the standard form of the equation:

where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:

where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10

b = 
b = 2


y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5
Is it 905m and 7mm added together to get the blank?
Answer:
x = 20
Step-by-step explanation:
15/9 = x/12
180 = 9x
x = 20
Answer:
m<-2
Step-by-step explanation:
-4m-3.65>4.35
-4m>4.35+3.65
-4m>8
4m<-8 (the greater than or less than sign flips when you multiply or divide by the - sign)
m<-2 (divide both sides by 4)