I will give Brainiest if you are right

Mathematics

1 answer:

ira [324]3 years ago

8 0

The answer is H. 2x>12

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Regroup hundreds as Tens:<br><br> 8 hundreds 9 tens =

Lilit [14]

89 tens because 8 x10 is 80 add the 9
89

7 0

4 years ago

How many different 10 person committees can be selected from a pool of 23 people?

Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

$C(n,r)=\dfrac{n!}{(n-r)!r!}$

Where $n$ represents the number of objects/people in the set and $r$ represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

$C(23,10)=\dfrac{23!}{(23-10)!10!}$

$=\dfrac{23!}{13!\times10!}$

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

$=1,144,066$

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

4 0

3 years ago

Read 2 more answers

The school cafeteria surveyed students to see what their favorite lunch is, and the

Sergio039 [100]

Answer:

40%

Step-by-step explanation:

Degree representing students who prefer burgers = 144°

Percentage of students who like burger = $\frac{144}{360} \times 100$