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2 years ago

7

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

an average of 85?
77, 95, 89, 86

1 answer:

Schach [20]2 years ago

6 0

Where are the following grades ? how am i supposed to answer without all parts of the question .

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Please help me on this

Nastasia [14]

Answer:

Points H, J, G, and K

Step-by-step explanation:

For quadrats the right top is 1

left top is 2

left bottom is 3

right bottom is 4

and it is asking for the forth one so look at the right bottom "square"

G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...

G is 3 and 4

K is 1 and 4

5 0

2 years ago

Read 2 more answers

If h=5, then 6h-4 equals<br>

Dovator [93]

6h-4

1. Substitute 5 for h
6(5)-4
30-4 =26

8 0

3 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago

insens350 [35]

Answer:

.

Step-by-step explanation:

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2 years ago

Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va

Nat2105 [25]

Answer:

(a <em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>+</u></em><em><u>7</u></em><em><u>a</u></em><em><u>+</u></em><em><u>1</u></em><em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>÷</u></em><em><u>(</u></em><em><u>a</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em>

5 0

2 years ago