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Alex73 [517]
2 years ago
13

Which graft represent -3x+5y=-15

Mathematics
1 answer:
azamat2 years ago
7 0

The graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

-3x + 5y = -15

The above function shows a linear function we can write it as:

5y = 3x - 15

y = (3x - 15)/5

If x = 0, y = -3

x = 1, y = -2.4

x = 2, y = -1.8

x = -1, y = -3.6

x = -2, y = -4.2

Thus, the graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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What is the equation of the line in the graph
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In this equation, 'm' is the slope, and 'b' is the y-intercept

When you're trying to find a slope, remember that the equation is \frac{rise}{run}

When finding the rise and run, look at two points that are on the graph AND on the line as well. Essentially, make sure the points you're using are integers.

In this, case, the rise is -3, and the run is 2. This means that the slope is  \frac{-3}{2}

Now we have the first part of our equation:

y = - \frac{3}{2} + b

But wait! How do we find b?

Sometimes you have to input x in order to find it, but only when you're not supplied with a graph. In this case, all you have to do is look!

The point of the line that is on the y-axis is called the y-intercept.

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Now we have our complete equation!

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Good luck!

3 0
3 years ago
-3w-3x-7w+4x-2w<br><br><br> ......
valkas [14]

Answer:

− 1 2 +

Step-by-step explanation:

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A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

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