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2 years ago

Which graft represent -3x+5y=-15

1 answer:

azamat2 years ago

7 0

The graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

-3x + 5y = -15

The above function shows a linear function we can write it as:

5y = 3x - 15

y = (3x - 15)/5

If x = 0, y = -3

x = 1, y = -2.4

x = 2, y = -1.8

x = -1, y = -3.6

x = -2, y = -4.2

Thus, the graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

Learn more about the function here:

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Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°.

inna [77]

Answer:

First part

The answer is (5 square root 2, 45°), (-5 square root 2, 225°) ⇒ answer (d)

Second part

The equation in standard form for the hyperbola is y²/81 - x²/19 = 1 ⇒ answer(b)

Step-by-step explanation:

First part:

* Lets study the Polar form and the Cartesian form

- The important difference between Cartesian coordinates and

polar coordinates:

# In Cartesian coordinates there is exactly one set of coordinates

for any given point.

# In polar coordinates there is an infinite number of coordinates

for a given point. For instance, the following four points are all

coordinates for the same point.

# In the polar the coordinates the origin is called the pole, and

the x axis is called the polar axis.

# The angle measurement θ can be expressed in radians

or degrees.

- To convert from Cartesian Coordinates (x , y) to

Polar Coordinates (r , θ)

# r = ± √(x² + y²)

# θ = tan^-1 (y / x)

* Lets solve the problem

- The point in the Cartesian coordinates is (5 , 5)

∵ x = 5 and y = 5

∴ r = ± √(5² + 5²) = ± √50 = ± 5√2

∴ tanФ = (5/5) = 1

∵ tanФ is positive

∴ Angle Ф could be in the first or third quadrant

∵ Ф = tan^-1 (1) = 45°

∴ Ф in the first quadrant is 45°

∴ Ф in the third quadrant is 180 + 45 = 225°

* The answer is (5√2 , 45°) , (-5√2 , 225°)

Second part:

* Lets study the standard form of the hyperbola equation

- The standard form of the equation of a hyperbola with

center (0 , 0) and transverse axis parallel to the y-axis is

y²/a² - x²/b² = 1, where

• the length of the transverse axis is 2a

• the coordinates of the vertices are (0 , ±a)

• the length of the conjugate axis is 2b

• the coordinates of the co-vertices are (±b , 0)

• the coordinates of the foci are (0 , ± c),

• the distance between the foci is 2c, where c² = a² + b²

* Lets solve our problem

∵ The vertices are (0 , 9) and (0 , -9)

∴ a = ± 9 ⇒ a² = 81

∵ The foci at (0 , 10) , (0 , -10)

∴ c = ± 10

∵ c² = a² + b²

∴ (10)² = (9)² + b² ⇒ 100 = 81 + b² ⇒ subtract 81 from both sides

∴ b² = 19

∵ The equation is y²/a² - x²/b² = 1

∴ y²/81 - x²/19 = 1

* The equation in standard form for the hyperbola is y²/81 - x²/19 = 1

3 0

3 years ago

B) 8xy +4y² factorise

m_a_m_a [10]

Answer:

The answer is: 4y(2x+y)

Step-by-step explanation:

8 0

1 year ago

Here is a sketch of a curve.

Ugo [173]

Answer:

The turning point of the graph is at (3,-16)

Step-by-step explanation:

The general equation of curve is given as:

y = x² + ax + b

The two point for which the equation satisfies is (0,-7) and (7,0).

Substitute (0,-7) in the general equation:

y = x² + ax + b

-7 = 0² + a(0) + b

b = -7

Substitute (7,0) in the general equation:

y = x² + ax + b

0 = 7² + 7a + b

Where b = -7

0 = 49 + 7a - 7

0 = 42 + 7a

a = -6

The equation of the curve is:

a = -6 and b = -7

y = x² + ax + b

y = x² - 6x - 7

Graph of the equation is attached below.

We can see that the the turning point of the graph is at (3,-16)

5 0

3 years ago

Which functions have graphs that are less steep than the graph of f(x)= -4x^2

LiRa [457]

TTese are all parabolas whose axis of symmetry is the y axis. The negative coefficient means they open downwards and the positive mean they open upwards. The higher the absolute value of the coefficient is the greater the slope, so 2x^2 will be steeper than x^2 and -4x^2 will be steeper than - 2x^2.

So h(x) and j(x) are the answers.

8 0

3 years ago

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kirill115 [55]

Answer:

Is this a complete question?

7 0

3 years ago