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stich3 [128]
3 years ago
8

Circle A contains points B, C, D, and E. BC and DĚ intersect on the exterior of OA at the point F. 68% D 26° Find the measure of

SCFE.

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

6

Step-by-step explanation:

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nataly862011 [7]

Answer:

You can use the equation a^2+b^2=c^2 using this you can find that the value of the 3rd side is 5 hope this helps <3

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Complete this table<br> 3°<br> 3<br> 32<br> 38<br> 34<br> 35<br> 36<br> 1<br> 3<br> 9<br> 27<br> 729
sveta [45]

3⁴= 3×3×3×3= 81

3⁵= 3×3×3×3×3= 243

hope it helps! please mark me brainliest

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Find 3/7 • 9/10 as a fraction
Lynna [10]

Answer:

27/70

Step-by-step explanation:

This is simple: First, you multiply the numerators. 3x9 is 27. That is the numerator to your answer.

Next, you multiply the denominators. 7x10 is 70. That's the denominator to the answer.

Put them together and you get 27/70.

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3 years ago
Find the zeros of the function f(x)=x2+2x-3
Lerok [7]

Answer:

x = -1 and x = 3

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3 0
3 years ago
Given that p+q=97 and q-p=-27, find the values of p and q.
Ber [7]

Answer:

p=62 q= 35

Step-by-step explanation:

solving \: the \: equation \: simultaneously \\ q + p = 97 -  -  -  - (1) \\ q - p =  - 27 -  -  -  -  - (2) \\ subtracting \: equation \: (2)from \: one(1) \\ q - q = 0 \\ p + p = 97 -  - 27 \\ 2p = 97 + 27 \\ 2p = 124 \\ dividing \: bothsides \: by \: 2 \\  \frac{2p}{p}  =  \frac{124}{2}  \\ p = 62 \\ put \: p \: = 62 \: into \: equation \: (1) \\ q + 62 = 97 \\ q = 97 - 62 \\ q = 35 \\ therefore \: p = 62 \:  \: and \: q = 35 \\

<h2>hope this helps</h2>

<h2>please rate and mark brainliest</h2>
8 0
2 years ago
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