Answer:
Step-by-step explanation:
(1 , -2) x₁ =1 & y₁ = -2
(-3,10) x₂= -3 & y₂ = 10
First we need to find the slope.
![=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B10-%5B-2%5D%7D%7B-3-1%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B10%2B2%7D%7B-4%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B12%7D%7B-4%7D%5C%5C%5C%5C%5C%5C%3D%20-%203)
m = -3
Equation of the line: y = mx + b
y = -3x + b
To find the value of b, take one of the point and substitue in the above equaiton.
(1 , -2)
-2 = -3*1 + b
-2 = -3 + b
-2 + 3 = b
b = 1
Equation of the line:
y = -3x + 1
So first, we multiply out the brackets.
-15x - 18 + 2 = 17 + 16x -1
Then, bring all the terms onto one side so you can solve.
-15x-18+2-17-16x+1=0
Then, we simplify this.
-31x-32=0
Then, isolate x
-31x=32
x=32/-31 or -1.03 (nearest hundredth )
If it is delayed by a month, a possible adjustment to the equation could look something like this:
S = 2(t-1)^2 + 100
These type of transformations are called horizontal shifts, aka "shift along the x-axis". So the answer is A.
Answer:
no
Step-by-step explanation:
because it is nor a solution
<h2>Given :- </h2>
- wide of the hall (Breadth) = 10m
<h2>To Find :- </h2>
- Surface area of the walls (Four walls area)
<h2>Formula :- </h2>
Four walls area of the hall = 2h(l+b)
where,
<h2>Solution : - </h2>
By substituting values according to the formula,
➙ 2 × 4m(12m + 10m)
➙ 8m(22m)
➠ 176m²
It's option B
<h3><u>Hence, The surface area of the walls is (B) 176m²</u></h3>
<h2 /><h2 />
