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iren [92.7K]
2 years ago
15

Please help me asap.

Mathematics
2 answers:
crimeas [40]2 years ago
4 0
4:2
6:3
8:4
10:5
4+2=6
2+1=3
Hope this helps ฅ^•ﻌ•^ฅ
charle [14.2K]2 years ago
3 0

Answer:

X Y

6. : 3

8. : 4

Step-by-step explanation:

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the sum of two numbers is 45. the greater number is 9 more than the other number. Find each number. use a system of linear equat
SpyIntel [72]

Answer:

18 and 27

Step-by-step explanation:

Let x = first (smaller) number

Let y = second (larger) number

Sum of two numbers is 45:

⇒ x + y = 45

The greater number is 9 more than the other number:

⇒ y = x + 9

Substitute  y = x + 9  into  x + y = 45  and solve for x:

⇒ x + (x + 9) = 45

⇒ 2x + 9 = 45

⇒ 2x = 36

⇒ x = 18

Substitute found value for x into  y = x + 9  and solve for y:

⇒ y = 18 + 9

⇒ y = 27

Therefore, the two numbers are 18 and 27

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2 years ago
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What must be true to define the measure of a distance of an arc between the points A and B on a circle? A unit of measure must b
Leno4ka [110]
A.) A unit of measure must be defined for distance    
6 0
3 years ago
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Al's awesome autos advertised a special sale on cars - Dealer cost plus 5%!! Jack and Margaret boughta luxury sedan for $23,727.
Marat540 [252]
05/23727.90=100/x
105x=23727.90x100
105x=2372790
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5 0
3 years ago
Solve for W
umka2103 [35]

In this equation w = -1.1

In order to find this, get all w values to the right side and all numbers to the left side.

-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms

-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides

-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides

13.8w = -15.18 -----> divide both sides by 13.8

w = -1.1

4 0
3 years ago
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The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
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