Question

The formula P=a+b+c gives the perimeter P of a triangle with side lengths a,b, and c. How much greater is the is the perimeter of triangular field with sides that measure 33 yards, 56 yards, and 65 yards than the perimeter of a triangular field with sides that measure 26 yards, 49 yards, and 38 yards?

Answer 1

(154-113)
41 yards bigger

Answer 2

Answer : 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

Step-by-step explanation :

First we have to calculate the perimeter of 1st triangle.

$P_1=a+b+c$

Given:

a = 33 yards

b = 56 yards

c = 65 yards

$P_1=33+56+65$

$P_1=154\text{ yards}$

Now we have to calculate the perimeter of 2nd triangle.

$P_2=a+b+c$

Given:

a = 26 yards

b = 49  yards

c = 38 yards

$P_2=26+49+38$

$P_2=113\text{ yards}$

Now we have to calculate which triangle has greater perimeter and how much greater.

$P_1-P_2=(154-113)\text{ yards}=41\text{ yards}$

Therefore, 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.