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son4ous [18]
3 years ago
6

Please help, solve for x

Mathematics
1 answer:
madreJ [45]3 years ago
7 0

Answer: x=12

First, you do 8 squared = 4(4+x)

Then, you distribute and becomes a two-step equation.

64=16+4x.

So x=12.

Hope it helps :) Brainliest?

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Ayuda en matemáticas plis
Semenov [28]

Answer:

A-2515.57647469

Step-by-step explanation:

3 0
3 years ago
A circle has a circumference of 10. It has an arc length of 9/2. What is the central angle of the arc in degrees?
dem82 [27]

Answer: The central angle of the arc is 162 degrees.

Step-by-step explanation: The information available are as follows;

Circumference of the circle equals 10. Length of an arc equals 9/2. The circumference of a circle is given as;

Circumference = 2Pi x r

That means 2Pi x r = 10.

Also the length of an arc along the same circle is 9/2. Length of an arc is calculated as;

Length of arc = (X/360) x 2Pi x r

Where X is the central angle of the arc

That means;

9/2 = (X/360) x 2Pi x r

We can now substitute for the known values as follows

Length of an arc = (X/360) x 2Pi x r

9/2 = (X/360) x 10

9/2 = 10X/360

By cross multiplication we now have

(9 x 360)/(2 x 10) = X

3240/20 = X

162 = X

The angle at the center of the arc is 162 degrees.

6 0
3 years ago
Read 2 more answers
What is the solution to the linear equation?<br>2/5 + p = 4/5 + 3/5p​
N76 [4]

Answer:

<h2>p = 1</h2>

Step-by-step explanation:

\frac{2}{5}  + p =  \frac{4}{5}  +  \frac{3}{5} p

Multiply through by the LCM

The LCM for the equation is 5

That's

5 \times  \frac{2}{5}  + 5p = 5 \times  \frac{4}{5}  +  \frac{3}{5}p  \times 5

We have

2 + 5p = 4 + 3p

Group like terms

5p - 3p = 4 - 2

2p = 2

Divide both sides by 2

We have the final answer as

<h3>p = 1</h3>

Hope this helps you

4 0
3 years ago
How far is a chord of length 8 cm from the centre of a circle of radius 5 cm
ivann1987 [24]
  • Answer:

<em>OB = 3 cm</em>

  • Step-by-step explanation:

<em>AO = radius = 5 cm</em>

<em>AB = 8cm/2 = 4 cm</em>

<em>Pythagora</em>

<em>OB² = AO² - AB²</em>

<em>= (5cm)² - (4cm)²</em>

<em>= 25cm² - 16cm²</em>

<em>= 9 cm²</em>

<em>OB = √9cm²</em>

<em>= 3 cm</em>

8 0
3 years ago
Please help with this 7th grade math I need to pass this test
kari74 [83]

<u>Area of triangle = (1/2) × Base × Height</u>

Area of bigger triangle = (1/2) × 15 cm × 10 cm

Area of bigger triangle = (1/2) × 150 sq. cm

Area of bigger triangle = 75 sq. cm

Similarly,

Area of smaller triangle = (1/2) × 12 cm × 5 cm

Area of smaller triangle = (1/2) × 60 sq. cm

Area of smaller triangle = 30 sq. cm

Area of shaded region = Area of bigger triangle - Area of smaller triangle

Area of shaded region = 75 sq. cm - 30 sq. cm

Area of shaded region = 45 sq. cm

<u>Answer</u><u> </u><u>:</u>

Area of shaded region in sq. cm = 45

7 0
3 years ago
Read 2 more answers
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