Please help thank you

Geraldine is asked to explain the limits on the range of an exponential equation using the function f(x) = 2^x. She makes these

GalinKa [24]

General Idea:

Domain is the values of x which gives a defined output to the function, and Range is the values of y that we get by substituting domain values of x. For the function f(x) = a^x, where a > 0, the domain will be all real numbers and range will be all values greater than 0. That is the graph will be very close to x-axis but will never touch it.

Applying the concept:

From the attached table, we can notice that as x increases infinitely, the y-values are continually doubled for each single increase in x and as x decreases infinitely, the y-values are continually halved for each single decrease in x.

Option 1: "Statement 1 is incorrect because the y-values are increased by 2, not doubled".

Option 1 is INCORRECT because Statement 1 is TRUE & CORRECT.

Option 2: "Statement 2 is incorrect because the y-values are doubled, not halved".

Option 2 is INCORRECT because Statement 2 is TRUE & CORRECT.

Option 3: "The conclusion is incorrect because the range is limited to the set of the integers"

Option 3 is INCORRECT because, the range will be always greater than 0, because irrespective of how many times y is halved for each single decrease in x, the y will still be a positive fraction and won't be a negative.

Option 4: "The conclusion is incorrect because the range is limited to the set of positive real numbers"

Option 4 is CORRECT because y value will be positive irrespective of whatever x we substitute in the function.

8 0

3 years ago

Read 2 more answers

Where on the graph of 2x - 6y = 7 is the x-coordinate twice the y-coordinate?

Nikolay [14]

Answer:

The required point is P(-7, $\frac{-7}{2}$ ) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7

Step-by-step explanation:

Given equation of line is 2x-6y=7

To find point on graph whose x-coordinate twice the y-coordinate:

Let y be y-coordinate of point

Hence, x-coordinate of point will be 2y

The required point is P(2y,y) on equation of line 2x-6y=7

Now,

2x-6y=7

2(2y)-6y=7

-2y=7

y= $\frac{-7}{2}$

Thus,

The required point is P(-7, $\frac{-7}{2}$ )

Note: Figure show equation of line red line and point P as blue dot.

5 0

3 years ago

Pls help xdcdcdcdcdcd

AysviL [449]

Answer:

A

Step-by-step explanation:

YESYESYESYESYESx85

6 0

3 years ago

Omg pls help me i only have a few min left imma cry

hodyreva [135]

Answer:

option B

Step-by-step explanation:

since DA and CB are equal and originate from same line segmnet, they are parallel, so angle D and angle C are equal, angle A and anfle B are equal and angle E is the same for both,

4 0

3 years ago

The Parry Glitter Company recently loaned $300,000 to FIX 92, a local radio station. The radio station signed a noninterest-bear

melomori [17]

Answer:

The Parry Glitter Company

The Parry Glitter Company should record the Notes Receivable as $300,000.

It should also record the interest receivable per year as $24,000 and the advertising cost as $24,000 per year. These bring into the accounting records the interest revenue and also the advertising expense, which eventually cancel each other.

Step-by-step explanation:

a) Data and Calculations:

Notes Receivable = $300,000

If the notes receivable are repaid at the end of 3 years and it is assumed that the interest on the notes receivable = 8%

Therefore, the cost of the free advertising will be equal to $24,000 ($300,000 * 8%), which is the cost of the interest to the radio station.

8 0

3 years ago