First find the slope, take derivative of both sides with respect to x.
2y dy/dx=3x^2+6x
solve for dy/dx
dy/dx=[3x^2+6x]/2y
plug in given vales of (1,2(
dy/dx=9/4
now you have everything you need to plug into point slope form
y-2=(9/4)(x-1)
answer is y=(9/4)x+(1/4)
Answer:
The maximum number of quarters that he could have is 13
Step-by-step explanation:
Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then
→ x + 10 >= 20
→ x >= 10 (1)
His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.
→ (x * 25) + (10 * 10) <= (4.25 * 100)
→ 25x + 100 <= 425
→ 25x <= 325
→ x <= 13 (2)
If we combine the equation 1 and 2:
10 <= x <= 13
The maximum value of x is 13
Answer:
Step-by-step explanation:
It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus
OC is the radius of the circle and is equal to 
.
Now, From ΔAOC, using the Pythagoras theorem, we get
⇒
⇒
⇒
⇒
Answer:
3. (x-6)
Step-by-step explanation:
x^2-5x-6
--
Find factors of -6 that could be added that equals to -5
Factors=
-6 and 1
x^2-5x-6 factored is (x-6)(x+1)
so the answer would be (3) (x-6)
80 is a number divisible by 2,8,10!
