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Sophie [7]
3 years ago
10

Please help ASAP. I will award brainliest.

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

what's the answer chocies

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Step-by-step explanation:

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What is the missing value in the table below?
Firlakuza [10]

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is 60

Step-by-step explanation:

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3 years ago
Which inequality is NOT true if y= -5?
Mila [183]

Answer: A

Step-by-step explanation:

2y - 10 > 13 y = -5

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3 0
2 years ago
To get to the other side of the lake, one can drive around it on Lake Road, go over the bridge or ride the ferry. How many diffe
Alexus [3.1K]
The answer is 9, here are all the possible combinations...

road, road
road, bridge
road, ferry
bridge, bridge
bridge, ferry
bridge, road
ferry, ferry
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Cheers!
8 0
3 years ago
Read 2 more answers
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0
4 years ago
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