See the picture, please!!
Answer:
See attachment
Step-by-step explanation:
We want to graph
on the interval -10 to 10.
Let
be the parent absolute value function.
We can easily graph
, if we use translation.
When the parent function is shifted downwards by 12 units, we obtain the graph of
.
The parent function is a v-shaped graph with vertex at the origin.
We shift the parent function down so that its vertex is now at (0,-12) to get the graph of
.
See attachment for the graph of
on the specified interval.
X(a+b)-y(a+b)
*factor out (a+b)*
=(a+b)(x-y)
Answer:
X²+y²+2x-10y+18=0 is the equation of circle
Step-by-step explanation:
Eqn of circle is: (x-h) ²+(y-k)²=r²
At (h, k) =(-1,5) and r=8 where h, k are center and r is radius.
Eqn is :(x+1)²+(y-5)²=8²
Or, x²+2x+1+y²-10y+25=8
Or, x²+y²+2x-10y+18=0 is the equation of circle