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Marta_Voda [28]
3 years ago
13

Cuanto es el 9% de 347.00

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

No se?

Step-by-step explanation:

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What is the answer for this question?
grandymaker [24]

Answer:

A

Step-by-step explanation:

\frac{11\pi }{6} is in the fourth quadrant where tan < 0

The related acute angle = 2π - \frac{11\pi }{6} = \frac{\pi }{6}

Hence

tan( \frac{11\pi }{6} )

= - tan(\frac{\pi }{6} )

= - \frac{1}{\sqrt{3} }

= - \frac{1}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} }

= - \frac{\sqrt{3} }{3} → A

5 0
3 years ago
Reflection across y = -x please I need help I will mark you brainless
tresset_1 [31]
Answer is
U= (-2,2)
V=(-2,4)
W= (-4,3)

Step by step
Find points for the triangle.
Using the rule for reflection across y axis.

The rule for a reflection over the y -axis is (x,y)→(−x,y)

U (2,2) ➡️ (-2,2)

V (2,4) ➡️ (-2,4)

W (4,3) ➡️ (-4,3)

4 0
1 year ago
Please answer thxxxx
Llana [10]
B. 13

12^2 + 5^2 = c^2
169 = c^2
13 = c


please mark as brainliest :D
4 0
2 years ago
Read 2 more answers
Which is an equation of a direct proportion
Over [174]
K = y/x OR y = kx

hope it helps!
6 0
2 years ago
One bricklayer can build a wall in 6 hours. Another bricklayer could build the same wall in 4 hours. If they work together, how
Natasha2012 [34]

Answer:

they work together, it will take 2.4 hours to build the wall.

Step-by-step explanation:

One bricklayer can build a wall in 6 hours.

One hour work = \frac{1}{6}

Another bricklayer can build the same wall in 4 hours.

One hour work = \frac{1}{4}

They can together, how long will take them to build the wall.

Let's take "t" the time taken to build the wall.

The sum of their work rate = 1 (To build the wall)

\frac{t}{6} + \frac{t}{4} = 1

Now we have to solve this equation. Take LCD of 6 and 4.

The LCD (least common divisor) of 6 and 4 is 12.

\frac{2t + 3t}{12} = 1

5t = 12*1

5t = 12

Dividing both sides by 5, we get

t = \frac{12}{5}

t = 2.4 hours.

So, they work together, it will take 2.4 hours to build the wall.

6 0
3 years ago
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