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Anit [1.1K]
3 years ago
7

Rats took my points ps. your the rats

Mathematics
2 answers:
belka [17]3 years ago
6 0

Answer:

oop lol i must be a rat then

Step-by-step explanation:

geniusboy [140]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

I is be the top rat

I AM THE RAT LORD

BOW DOWN TO ME YOU PEASANTS

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What is the degree of the polynomial -2x^2 y^4 -1/2z<br> A.) 1<br> B.) 2<br> C.) 4<br> D.) 6
Ksju [112]

Answer:

3x2−2x+5 wrong

30x2+5x−6 RIGHT I THINK SO 6

x^−4x^+9 wrong

6 0
3 years ago
What is (2.5 x 10 to the third power) (6 x 10 to the fourth power)
Gelneren [198K]

Answer:

2,500) (60,000

brain pls

Step-by-step explanation:

5 0
3 years ago
8 2. PROVE: tane+cotes: sececsc? (Hint: Convert to sin's and cos's.
Luden [163]

\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1 \\\\[-0.35em] \rule{34em}{0.25pt}

\bf tan(\theta )+cot(\theta )=sec(\theta )csc(\theta ) \\\\[-0.35em] ~\dotfill\\\\ tan(\theta )+cot(\theta )\implies \cfrac{sin(\theta )}{cos(\theta )}+\cfrac{cos(\theta )}{sin(\theta )}\implies \cfrac{sin(\theta ) sin(\theta )+cos(\theta )cos(\theta )}{cos(\theta )sin(\theta )} \\\\\\ \cfrac{sin^2(\theta )+cos^2(\theta )}{cos(\theta )sin(\theta )}\implies \cfrac{1}{cos(\theta )sin(\theta )}\implies \cfrac{1}{cos(\theta )}\cdot \cfrac{1}{sin(\theta )}\implies sec(\theta )csc(\theta )

4 0
3 years ago
To fill out a function's ___ ___, you will need to use test numbers before and after each of the function's ___ and asymtopes
mr_godi [17]

Answer:

  C).  sign chart; zeroes

Step-by-step explanation:

A function potentially changes sign at each of its <em>zeros</em> and vertical asymptotes. So, to fill out a <em>sign chart</em>, you need to determine what the sign is on either side of each of these points. You can do that using test numbers, or you can do it by understanding the nature of the zero or asymptote.

<u>Examples:</u>

f1(x) = (x -3) . . . . changes sign at the zero x=3. Is positive for x > 3, negative for x < 3.

f2(x) = (x -4)^2 . . . . does not change sign at the zero x=4. It is positive for any x ≠ 4. This will be true for any even-degree binomial factor.

f3(x) = 1/(x+2) . . . . has a vertical asymptote at x=-2. It changes sign there because the denominator changes sign there.

f4(x) = 1/(x+3)^2 . . . . has a vertical asymptote at x=-3. It does not change sign there because the denominator is of even degree and does not change sign there.

4 0
4 years ago
Type the missing number in this sequence:<br> 58, 65, 72, ___, 86, 93
Free_Kalibri [48]

Answer:

79

Step-by-step explanation:

3 0
3 years ago
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