Answer:
The usual size of the container is 15 ounces.
Step-by-step explanation:
Consider the provided information.
A protein mix claims to contain a bonus of 20% more mix than the usual size container.
Let the usual size of the container was x ounces.
They increase 20% of usual size and the bonus size is 18 ounces.
Therefore, the new size should be:
(∴20%=
=0.20)
Hence, the usual size of the container is 15 ounces.
Answer:
m=17/40
Step-by-step explanation:
So you 5/7m - 1/7 = 9/56
You Simplify both sides Then
well I Don´t know I hope this helped u, I tried ^^¨
Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>The confidence interval is:
The margin of error is:
In which:
Assuming an uniform distribution, the standard deviation is given by:
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:
n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
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