PLS HELPPP<br> find the volume.

What is the quadratic. Formula?

balu736 [363]

Answer:

$x = \frac{ - b ± \sqrt{ {b }^{2} - 4ac } }{2a}$

Step-by-step explanation:

For example, we'll use this quadratic equation.

${x}^{2} + 5x + 6$

To understand how to plug it into the formula we need to know what each term represents.

$a {x}^{2} + bx + c$

So the equation above would be put into the formula like this.

$x = \frac{ - 5± \sqrt{ {5}^{2} - 4(1)(6) } }{2(1)}$

Then we would solve

$\frac{ - 5± \sqrt{25 - 24} }{2} \\ \\ = \frac{ -5±1}{2}$

Now, the equation will branch off into one that solves when addition and one when subtraction.

$\frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ \\ \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$

So x={-3, -2} (-3 and -2)

6 0

3 years ago

. A pack of baseball cards has 12 trading cards and 2 stickers. In a

erik [133]

Answer:
432 cards and 72 stickers
Explanation:
1 pack=12 cards + 2 stickers
So if we want 36 packs..
36 packs=433 cards + 72 stickers
We times everything by 36!

3 0

3 years ago

Round 9,526,789 to the nearest hundred thousand

tino4ka555 [31]

Answer:

9,500,000. the ten thousands place has a two, which is one less than 3, rendering the 6 in the thousand's place ineffective

Step-by-step explanation:

4 or less let it rest, 5 or more let it score

3 0

3 years ago

PLEASE HURRY<br> NO LINKS OR FILES OR I'LL REPORT<br> I CAN GIVE BRAINLIEST

marissa [1.9K]

Answer:

3 1/3

Step-by-step explanation:

2 + (-2/3)² ÷ 1/3

2 + 4/9 ÷ 1/3

2 + 4/9 × 3/1

2 + 12/9 = 2 + 4/3 = 2 + 1 1/3

= 3 1/3

5 0

2 years ago

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

PLS HELPPP find the volume.