PLS HELPPP find the volume.
1 answer:
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Answer:
Perimeter is 17.07
Step-by-step explanation:
We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.
We need to use the Pythagorean theorem to get the length of DE.
So the perimeter of DEF is 5 + 5 + 7.07 = 17.07
The complete question in the attached figure
step 1
find the tree height for an angle of elevation of 55°<span>
tan 55</span>°=opposite side angle 55°/adjacent side angle 55°
opposite side angle 55°=the tree height h1
adjacent side angle 55°=10 ft
so
tan 55°=h/10-------> h=10*tan 55°-----> h=14.28 ft
step 2
find the tree height for an angle of elevation of 75°
tan 75°=opposite side angle 75°/adjacent side angle 75°
opposite side angle 75°=the tree height h2
adjacent side angle 75°=10 ft
so
tan 75°=h2/10-------> h2=10*tan 75°-----> h2=37.32 ft
therefore
<span>the height of the tree is within the range [14.26,37.32]
</span>
Part 1) 4.2 ft
<span>the value is not in the interval [14.26,37.32]
therefore
it is </span>Not Reasonable
Part 2) 14.7 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 3) 24.4 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 4) 33.9 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 5) 39.1ft
the value is not in the interval [14.26,37.32]
therefore
it is Not Reasonable
Part 6) 58.7 ft
the value is not in the interval [14.26,37.32]
therefore
it is Not Reasonable
step 1
find the tree height for an angle of elevation of 55°<span>
tan 55</span>°=opposite side angle 55°/adjacent side angle 55°
opposite side angle 55°=the tree height h1
adjacent side angle 55°=10 ft
so
tan 55°=h/10-------> h=10*tan 55°-----> h=14.28 ft
step 2
find the tree height for an angle of elevation of 75°
tan 75°=opposite side angle 75°/adjacent side angle 75°
opposite side angle 75°=the tree height h2
adjacent side angle 75°=10 ft
so
tan 75°=h2/10-------> h2=10*tan 75°-----> h2=37.32 ft
therefore
<span>the height of the tree is within the range [14.26,37.32]
</span>
Part 1) 4.2 ft
<span>the value is not in the interval [14.26,37.32]
therefore
it is </span>Not Reasonable
Part 2) 14.7 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 3) 24.4 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 4) 33.9 ft
the value is in the interval [14.26,37.32]
therefore
it is Reasonable
Part 5) 39.1ft
the value is not in the interval [14.26,37.32]
therefore
it is Not Reasonable
Part 6) 58.7 ft
the value is not in the interval [14.26,37.32]
therefore
it is Not Reasonable