Answer:
C is the answer your looking for
Let number of fives = x then number of ones = 3x and number of tens = x - 1
so we can create the equation
x + 3x + x-1 + y = 26 where y = number of twenties
so
5x + y = 27
also we have the equation
5x + 3x + 10(x - 1) + 20y = 120
18x + 20y = 130..................................(1)
5x + y = 27 multiply by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x = 5, that is 5 fives
Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y = 40
y = 2 , that is 2 twenties
So the answer is there are (3x) = 15 ones , 5 fives, 4 tens and 2 twenties
I am assuming 28/0. The short answer is that it is infinity. (Or they may want undefined)
Here is a bit longer explination:
Let's start by taking 28/1, that gives 28. What about 28/0.5 that gives 56, and as we keep decreasing the denominator closer to zero then the quotient will become larger and larger. We we reach zero, the quotient becomes so large that it is considered infinity.
She made 20 oatmeal cookies
4/5 = 0.8
0.8 x 25 = 20
