Well every time it gets rid of a shell it grows 1 1/3 times larger. So so to see how much it grows after the first time you say
1 cm * 1 1/3 = 1 1/3 cm
to get the next one you do the same
1 1/3 cm * 1 1/3 cm = 16/9
It will keep going multiplying by 1 1/3. So so we can say in an equation that the
(initial size) * 1 1/3 *(number of shells) = length
Or 1cm * 1 1/3 * n = L
We we know the final length is 10cm
So 1 1/3 * n = 10cm
n = 7.5shells
so approximately 7 or 8 shells
This strategy works because if you subtract one number from another the sum of the two numbers should be the that is being subtracted from. (In this case, it's 200)
Chau’s height = c
c - 10 = 47
i think ?
Differentiating once, we have
Differentiating again,
as needed.
Answer:
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Step-by-step explanation:
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