Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎
-(-(-)(-)(-10x)) = -5
We need to cancel out the negatives, so we need to simplify this.
To make things a bit easier for you, we can begin by counting out how many negatives we have. After counting, you should have a negative number count of 5. However, one of the negatives is apart of (-10x) so we'll have 4 negatives and then an extra negative in with 10x.
Remember that "-" could also be looked at as "-1."
So, if we break this down into smaller parts and substitute "-" into "-1," then this'll look like this :
-1 × -1 × -1 × -1 × (-10x) = -5
Remember that a negative times a negative is always a positive.
So, since there are four negatives, then you just multiply it all together.
This results in 1 × (-10x) = -5
Simplify.
-10x = -5
Now, you simply divide both sides by -10.
-10x ÷ -10 = -5 ÷ -10
Simplify.
x = 1/2
~Hope I helped!~
Answer:
d. 2
Step-by-step explanation: