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olga_2 [115]
2 years ago
6

The function g(x) is graphed.

Mathematics
1 answer:
sergejj [24]2 years ago
3 0

g(1)=-1 :  We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1)=-1  is false.

g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.

So, g(0) =0 is true.

g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.

So, g(4)=-2 is false.

g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.

So, g(1) =1 is true.

g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.

So, g(-1)=1 is true.

g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.

So, g(4)=2 is false.

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Answer:

C. $538,021.66

Step-by-step explanation:

It is given that the money Seth withdraws was compounded every quarter for 35 years. So, we get,

Amount withdrawn every quarter, P = $4567

Rate of interest, r  = \frac{0.0101}{4} = 0.002525

Time period, n = 35 × 4 = 140

Now, as we know the formula for annuity as,

P=\frac{r \times PV}{1-(1+r)^{-n}}

where P = installments, PV = present value, r = rate of interest and n = time period.

This gives, PV=\frac{P \times [1-(1+r)^{-n}]}{r}

i.e. PV=\frac{4567 \times [1-(1+0.002525)^{-140}]}{0.002525}

i.e. PV=\frac{4567 \times [1-(1.002525)^{-140}]}{0.002525}

i.e. PV=\frac{4567 \times [1-0.7021]}{0.002525}

i.e. PV=\frac{4567 \times 0.2975}{0.002525}

i.e. PV=\frac{1358.68}{0.002525}

i.e. PV=538,091.08

So, the closest answer to initial value of the account is $538,021.66

Hence, option C is correct.

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