Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:

Then, the probability that at most 1 car will require major engine repair next year is:

Answer:8 days and 12 hours
Step-by-step explanation:30$ is each day
Answer:
f(-1) = 8
Step-by-step explanation:
f(-1) = x
f(-1) = -5(-1) + 3
f(-1) = 8
Answer:
After ten years his salary is x2
Step-by-step explanation: